5th Bc

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Frequently Asked Questions...

Triangle ABC has side lengths AB=x^2-5, BC=3x^2+8x, AC=16x+11, perimeter=24. wats X by usin completein square?

method.

thanks! best answer gets points!


Best Answer...

Answer:

24 = (x² - 5) + (3x² + 8x) + (16x + 11)
24 = 4x² + 24x + 6
4x² + 24x - 18 = 0
4(x² + 6x - 9/2) = 0
4(x² + 6x + 9 - 9 - 9/2) = 0
4((x + 3)² - 18/2 - 9/2) = 0
2((x + 3)² - 27/2) = 0
(x + 3)² - 27/2 = 0
(x + 3)² = 27/2
x + 3 = ± √(27/2)
x = ±√(27/2) - 3

However, the solution with the negative square root is outside the domain of the question (because each side must be greater than 0), so the solution is ONLY
x = √(27/2) - 3 ≈ 0.674